13531041131 has 2 divisors, whose sum is σ = 13531041132. Its totient is φ = 13531041130.

The previous prime is 13531041109. The next prime is 13531041133. The reversal of 13531041131 is 13114013531.

13531041131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13531041131 is a prime.

It is a super-2 number, since 2×13531041131² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13531041133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13531041097 and 13531041106.

It is not a weakly prime, because it can be changed into another prime (13531041133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765520565 + 6765520566.

It is an arithmetic number, because the mean of its divisors is an integer number (6765520566).

Almost surely, 2^13531041131 is an apocalyptic number.

13531041131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13531041131 is an equidigital number, since it uses as much as digits as its factorization.

13531041131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 13531041131 its reverse (13114013531), we get a palindrome (26645054662).

The spelling of 13531041131 in words is "thirteen billion, five hundred thirty-one million, forty-one thousand, one hundred thirty-one".