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13531142113 is a prime number
BaseRepresentation
bin11001001101000010…
…01101011111100001
31021221000020020110121
430212201031133201
5210202433021423
610114403200241
7656212544626
oct144641153741
937830206417
1013531142113
115813a82385
122757676081
13137843b888
1492510a34d
15542dbc45d
hex32684d7e1

13531142113 has 2 divisors, whose sum is σ = 13531142114. Its totient is φ = 13531142112.

The previous prime is 13531142077. The next prime is 13531142117. The reversal of 13531142113 is 31124113531.

13531142113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10892470689 + 2638671424 = 104367^2 + 51368^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13531142113 is a prime.

It is not a weakly prime, because it can be changed into another prime (13531142117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765571056 + 6765571057.

It is an arithmetic number, because the mean of its divisors is an integer number (6765571057).

Almost surely, 213531142113 is an apocalyptic number.

It is an amenable number.

13531142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13531142113 is an equidigital number, since it uses as much as digits as its factorization.

13531142113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1080, while the sum is 25.

Adding to 13531142113 its reverse (31124113531), we get a palindrome (44655255644).

The spelling of 13531142113 in words is "thirteen billion, five hundred thirty-one million, one hundred forty-two thousand, one hundred thirteen".