Base | Representation |
---|---|
bin | 11001001101000010… |
… | …01101111100000111 |
3 | 1021221000020022222101 |
4 | 30212201031330013 |
5 | 210202433101233 |
6 | 10114403212531 |
7 | 656212553152 |
oct | 144641157407 |
9 | 37830208871 |
10 | 13531143943 |
11 | 5813a83799 |
12 | 2757677147 |
13 | 137843c665 |
14 | 92510ac99 |
15 | 542dbcc7d |
hex | 32684df07 |
13531143943 has 2 divisors, whose sum is σ = 13531143944. Its totient is φ = 13531143942.
The previous prime is 13531143929. The next prime is 13531144019. The reversal of 13531143943 is 34934113531.
13531143943 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (34934113531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13531143943 - 229 = 12994273031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531144943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765571971 + 6765571972.
It is an arithmetic number, because the mean of its divisors is an integer number (6765571972).
Almost surely, 213531143943 is an apocalyptic number.
13531143943 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531143943 is an equidigital number, since it uses as much as digits as its factorization.
13531143943 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 58320, while the sum is 37.
The spelling of 13531143943 in words is "thirteen billion, five hundred thirty-one million, one hundred forty-three thousand, nine hundred forty-three".
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