Base | Representation |
---|---|
bin | 11110110001000011001100… |
… | …000111111001001111001100 |
3 | 122202002201010010000011212212 |
4 | 132301003030013321033030 |
5 | 120213423112011032300 |
6 | 1155441301522045552 |
7 | 40333655225320043 |
oct | 3661031407711714 |
9 | 582081103004785 |
10 | 135312074314700 |
11 | 3a12958a410368 |
12 | 13214477aa98b8 |
13 | 5a66b48b2c25a |
14 | 255b1d44cb55a |
15 | 1099b9e4c8935 |
hex | 7b10cc1f93cc |
135312074314700 has 18 divisors (see below), whose sum is σ = 293627201263116. Its totient is φ = 54124829725840.
The previous prime is 135312074314693. The next prime is 135312074314733. The reversal of 135312074314700 is 7413470213531.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 676560371474 + ... + 676560371673.
Almost surely, 2135312074314700 is an apocalyptic number.
135312074314700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135312074314700 is an abundant number, since it is smaller than the sum of its proper divisors (158315126948416).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135312074314700 is a wasteful number, since it uses less digits than its factorization.
135312074314700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1353120743161 (or 1353120743154 counting only the distinct ones).
The product of its (nonzero) digits is 211680, while the sum is 41.
The spelling of 135312074314700 in words is "one hundred thirty-five trillion, three hundred twelve billion, seventy-four million, three hundred fourteen thousand, seven hundred".
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