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13531314281 is a prime number
BaseRepresentation
bin11001001101000011…
…10111100001101001
31021221000112222122012
430212201313201221
5210203004024111
610114411005305
7656214162602
oct144641674151
937830488565
1013531314281
11581408a771
122757739835
13137849c054
14925152da9
15542e0348b
hex326877869

13531314281 has 2 divisors, whose sum is σ = 13531314282. Its totient is φ = 13531314280.

The previous prime is 13531314263. The next prime is 13531314287. The reversal of 13531314281 is 18241313531.

13531314281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8926470400 + 4604843881 = 94480^2 + 67859^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13531314281 is a prime.

It is a super-2 number, since 2×135313142812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13531314287) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765657140 + 6765657141.

It is an arithmetic number, because the mean of its divisors is an integer number (6765657141).

Almost surely, 213531314281 is an apocalyptic number.

It is an amenable number.

13531314281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13531314281 is an equidigital number, since it uses as much as digits as its factorization.

13531314281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8640, while the sum is 32.

The spelling of 13531314281 in words is "thirteen billion, five hundred thirty-one million, three hundred fourteen thousand, two hundred eighty-one".