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135313520460000 = 253546073715363
BaseRepresentation
bin11110110001000100100010…
…010100100000000011100000
3122202002211211220011222021220
4132301010202110200003200
5120213434042214210000
61155442101222015040
740334036115334101
oct3661044224400340
9582084756158256
10135313520460000
113a12a161757773
1213214800277480
135a6701961672c
14255b2d05b23a8
151099c364361a0
hex7b11225200e0

135313520460000 has 240 divisors, whose sum is σ = 444586757497344. Its totient is φ = 36024149952000.

The previous prime is 135313520459977. The next prime is 135313520460023. The reversal of 135313520460000 is 64025313531.

It is an interprime number because it is at equal distance from previous prime (135313520459977) and next prime (135313520460023).

It is a tau number, because it is divible by the number of its divisors (240).

It is a super-2 number, since 2×1353135204600002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 34562319 + ... + 38277681.

Almost surely, 2135313520460000 is an apocalyptic number.

135313520460000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135313520460000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222293378748672).

135313520460000 is an abundant number, since it is smaller than the sum of its proper divisors (309273237037344).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135313520460000 is an equidigital number, since it uses as much as digits as its factorization.

135313520460000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3716003 (or 3715980 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 135313520460000 its reverse (64025313531), we get a palindrome (135377545773531).

The spelling of 135313520460000 in words is "one hundred thirty-five trillion, three hundred thirteen billion, five hundred twenty million, four hundred sixty thousand".