Base | Representation |
---|---|
bin | 11001001101000100… |
… | …00001010101000001 |
3 | 1021221000122000201022 |
4 | 30212202001111001 |
5 | 210203011320213 |
6 | 10114411515225 |
7 | 656214420632 |
oct | 144642012501 |
9 | 37830560638 |
10 | 13531354433 |
11 | 5814107953 |
12 | 2757758b15 |
13 | 13784b43cc |
14 | 925163889 |
15 | 542e10308 |
hex | 326881541 |
13531354433 has 2 divisors, whose sum is σ = 13531354434. Its totient is φ = 13531354432.
The previous prime is 13531354399. The next prime is 13531354451. The reversal of 13531354433 is 33445313531.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13359429889 + 171924544 = 115583^2 + 13112^2 .
It is a cyclic number.
It is not a de Polignac number, because 13531354433 - 214 = 13531338049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13531354393 and 13531354402.
It is not a weakly prime, because it can be changed into another prime (13531354453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765677216 + 6765677217.
It is an arithmetic number, because the mean of its divisors is an integer number (6765677217).
Almost surely, 213531354433 is an apocalyptic number.
It is an amenable number.
13531354433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531354433 is an equidigital number, since it uses as much as digits as its factorization.
13531354433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 97200, while the sum is 35.
Adding to 13531354433 its reverse (33445313531), we get a palindrome (46976667964).
The spelling of 13531354433 in words is "thirteen billion, five hundred thirty-one million, three hundred fifty-four thousand, four hundred thirty-three".
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