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13531411277 is a prime number
BaseRepresentation
bin11001001101000100…
…01111001101001101
31021221000201220200122
430212202033031031
5210203020130102
610114413034325
7656215045436
oct144642171515
937830656618
1013531411277
11581414662a
1227577859a5
131378504247
1492517a48d
15542e220a2
hex32688f34d

13531411277 has 2 divisors, whose sum is σ = 13531411278. Its totient is φ = 13531411276.

The previous prime is 13531411199. The next prime is 13531411319. The reversal of 13531411277 is 77211413531.

13531411277 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7584842281 + 5946568996 = 87091^2 + 77114^2 .

It is a cyclic number.

It is not a de Polignac number, because 13531411277 - 232 = 9236443981 is a prime.

It is a super-2 number, since 2×135314112772 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13531411177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765705638 + 6765705639.

It is an arithmetic number, because the mean of its divisors is an integer number (6765705639).

Almost surely, 213531411277 is an apocalyptic number.

It is an amenable number.

13531411277 is a deficient number, since it is larger than the sum of its proper divisors (1).

13531411277 is an equidigital number, since it uses as much as digits as its factorization.

13531411277 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17640, while the sum is 35.

The spelling of 13531411277 in words is "thirteen billion, five hundred thirty-one million, four hundred eleven thousand, two hundred seventy-seven".