Base | Representation |
---|---|
bin | 10000001000010… |
… | …11111010101111 |
3 | 100102121201110002 |
4 | 20010023322233 |
5 | 234120040434 |
6 | 21232134515 |
7 | 3232105502 |
oct | 1004137257 |
9 | 312551402 |
10 | 135315119 |
11 | 6a422285 |
12 | 3939743b |
13 | 22059b24 |
14 | 13d85139 |
15 | bd2d57e |
hex | 810beaf |
135315119 has 2 divisors, whose sum is σ = 135315120. Its totient is φ = 135315118.
The previous prime is 135315113. The next prime is 135315133. The reversal of 135315119 is 911513531.
135315119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135315119 is a prime.
It is a super-2 number, since 2×1353151192 = 36620362859968322, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 135315091 and 135315100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135315113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67657559 + 67657560.
It is an arithmetic number, because the mean of its divisors is an integer number (67657560).
Almost surely, 2135315119 is an apocalyptic number.
135315119 is a deficient number, since it is larger than the sum of its proper divisors (1).
135315119 is an equidigital number, since it uses as much as digits as its factorization.
135315119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2025, while the sum is 29.
The square root of 135315119 is about 11632.5026971843. The cubic root of 135315119 is about 513.3916189604.
The spelling of 135315119 in words is "one hundred thirty-five million, three hundred fifteen thousand, one hundred nineteen".
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