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1353152131 is a prime number
BaseRepresentation
bin101000010100111…
…0111011010000011
310111022012020202121
41100221313122003
510232401332011
6342134425111
745350413642
oct12051673203
93438166677
101353152131
11634901251
12319202197
13187458046
14cb9d9359
157dbdde71
hex50a77683

1353152131 has 2 divisors, whose sum is σ = 1353152132. Its totient is φ = 1353152130.

The previous prime is 1353152117. The next prime is 1353152149. The reversal of 1353152131 is 1312513531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1353152131 - 211 = 1353150083 is a prime.

It is a super-2 number, since 2×13531521312 = 3662041379259682322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1353152096 and 1353152105.

It is not a weakly prime, because it can be changed into another prime (1353156131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676576065 + 676576066.

It is an arithmetic number, because the mean of its divisors is an integer number (676576066).

Almost surely, 21353152131 is an apocalyptic number.

1353152131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353152131 is an equidigital number, since it uses as much as digits as its factorization.

1353152131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1350, while the sum is 25.

The square root of 1353152131 is about 36785.2162016210. The cubic root of 1353152131 is about 1106.0689698517.

Adding to 1353152131 its reverse (1312513531), we get a palindrome (2665665662).

The spelling of 1353152131 in words is "one billion, three hundred fifty-three million, one hundred fifty-two thousand, one hundred thirty-one".