Base | Representation |
---|---|
bin | 11110110001001010100101… |
… | …111111001001111001000000 |
3 | 122202010110122011112120121110 |
4 | 132301022211333021321000 |
5 | 120214040402223032000 |
6 | 1155445054440323320 |
7 | 40334356232166213 |
oct | 3661124577117100 |
9 | 582113564476543 |
10 | 135320024424000 |
11 | 3a13199a002129 |
12 | 13215b16473540 |
13 | 5a67814c24940 |
14 | 255b74a2c977a |
15 | 1099eb741b850 |
hex | 7b12a5fc9e40 |
135320024424000 has 1344 divisors, whose sum is σ = 498951792218880. Its totient is φ = 32114869862400.
The previous prime is 135320024423959. The next prime is 135320024424071. The reversal of 135320024424000 is 424420023531.
135320024424000 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1353200244240002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 51708070692 + ... + 51708073308.
It is an arithmetic number, because the mean of its divisors is an integer number (371243893020).
Almost surely, 2135320024424000 is an apocalyptic number.
135320024424000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 135320024424000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (249475896109440).
135320024424000 is an abundant number, since it is smaller than the sum of its proper divisors (363631767794880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135320024424000 is a wasteful number, since it uses less digits than its factorization.
135320024424000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2825 (or 2752 counting only the distinct ones).
The product of its (nonzero) digits is 23040, while the sum is 30.
Adding to 135320024424000 its reverse (424420023531), we get a palindrome (135744444447531).
The spelling of 135320024424000 in words is "one hundred thirty-five trillion, three hundred twenty billion, twenty-four million, four hundred twenty-four thousand".
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