Base | Representation |
---|---|
bin | 10011101100010001001… |
… | …000001000110110100101 |
3 | 11210100211222101022220021 |
4 | 103230101020020312211 |
5 | 134132324210404300 |
6 | 2513352532035141 |
7 | 166523415410335 |
oct | 23542110106645 |
9 | 4710758338807 |
10 | 1353202044325 |
11 | 48198730456a |
12 | 19a314762ab1 |
13 | 9a7b6370341 |
14 | 496d12770c5 |
15 | 252ee96dd1a |
hex | 13b11208da5 |
1353202044325 has 12 divisors (see below), whose sum is σ = 1723321091140. Its totient is φ = 1053303212160.
The previous prime is 1353202044211. The next prime is 1353202044347. The reversal of 1353202044325 is 5234402023531.
It can be written as a sum of positive squares in 6 ways, for example, as 101358820161 + 1251843224164 = 318369^2 + 1118858^2 .
It is not a de Polignac number, because 1353202044325 - 27 = 1353202044197 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 731459640 + ... + 731461489.
Almost surely, 21353202044325 is an apocalyptic number.
It is an amenable number.
1353202044325 is a deficient number, since it is larger than the sum of its proper divisors (370119046815).
1353202044325 is a wasteful number, since it uses less digits than its factorization.
1353202044325 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1462921176 (or 1462921171 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 1353202044325 its reverse (5234402023531), we get a palindrome (6587604067856).
The spelling of 1353202044325 in words is "one trillion, three hundred fifty-three billion, two hundred two million, forty-four thousand, three hundred twenty-five".
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