Base | Representation |
---|---|
bin | 10011101100010100100… |
… | …110000000100100000011 |
3 | 11210101000000211021011221 |
4 | 103230110212000210003 |
5 | 134132434103100324 |
6 | 2513402410415511 |
7 | 166525022651026 |
oct | 23542446004403 |
9 | 4711000737157 |
10 | 1353260206339 |
11 | 481a0711a548 |
12 | 19a330131597 |
13 | 9a7c5425832 |
14 | 496d8c971bd |
15 | 25304b0c0e4 |
hex | 13b14980903 |
1353260206339 has 2 divisors, whose sum is σ = 1353260206340. Its totient is φ = 1353260206338.
The previous prime is 1353260206321. The next prime is 1353260206357. The reversal of 1353260206339 is 9336020623531.
It is a balanced prime because it is at equal distance from previous prime (1353260206321) and next prime (1353260206357).
It is a cyclic number.
It is not a de Polignac number, because 1353260206339 - 211 = 1353260204291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1353260206295 and 1353260206304.
It is not a weakly prime, because it can be changed into another prime (1353260206399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676630103169 + 676630103170.
It is an arithmetic number, because the mean of its divisors is an integer number (676630103170).
Almost surely, 21353260206339 is an apocalyptic number.
1353260206339 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353260206339 is an equidigital number, since it uses as much as digits as its factorization.
1353260206339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 524880, while the sum is 43.
The spelling of 1353260206339 in words is "one trillion, three hundred fifty-three billion, two hundred sixty million, two hundred six thousand, three hundred thirty-nine".
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