Base | Representation |
---|---|
bin | 11110110001010110001010… |
… | …010000111101111101000111 |
3 | 122202011122200201121021101111 |
4 | 132301112022100331331013 |
5 | 120214241321210433133 |
6 | 1155454511104105451 |
7 | 40335306061631404 |
oct | 3661261220757507 |
9 | 582148621537344 |
10 | 135332444233543 |
11 | 3a137192729937 |
12 | 13218401905287 |
13 | 5a68a4404557b |
14 | 255c1a79872ab |
15 | 109a4929651cd |
hex | 7b158a43df47 |
135332444233543 has 2 divisors, whose sum is σ = 135332444233544. Its totient is φ = 135332444233542.
The previous prime is 135332444233397. The next prime is 135332444233579. The reversal of 135332444233543 is 345332444233531.
It is a strong prime.
It is an emirp because it is prime and its reverse (345332444233531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135332444233543 - 233 = 135323854298951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135332444233043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67666222116771 + 67666222116772.
It is an arithmetic number, because the mean of its divisors is an integer number (67666222116772).
Almost surely, 2135332444233543 is an apocalyptic number.
135332444233543 is a deficient number, since it is larger than the sum of its proper divisors (1).
135332444233543 is an equidigital number, since it uses as much as digits as its factorization.
135332444233543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18662400, while the sum is 49.
The spelling of 135332444233543 in words is "one hundred thirty-five trillion, three hundred thirty-two billion, four hundred forty-four million, two hundred thirty-three thousand, five hundred forty-three".
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