Base | Representation |
---|---|
bin | 10011101100011001010… |
… | …010100101010011010001 |
3 | 11210101012112002101210022 |
4 | 103230121102211103101 |
5 | 134133114241000032 |
6 | 2513414303313225 |
7 | 166530000461144 |
oct | 23543122452321 |
9 | 4711175071708 |
10 | 1353339000017 |
11 | 481a47647394 |
12 | 19a3525ab815 |
13 | 9a808852b04 |
14 | 4970552805b |
15 | 2530b9c3512 |
hex | 13b194a54d1 |
1353339000017 has 2 divisors, whose sum is σ = 1353339000018. Its totient is φ = 1353339000016.
The previous prime is 1353338999993. The next prime is 1353339000029. The reversal of 1353339000017 is 7100009333531.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1257170167696 + 96168832321 = 1121236^2 + 310111^2 .
It is a cyclic number.
It is not a de Polignac number, because 1353339000017 - 234 = 1336159130833 is a prime.
It is not a weakly prime, because it can be changed into another prime (1353339000077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676669500008 + 676669500009.
It is an arithmetic number, because the mean of its divisors is an integer number (676669500009).
Almost surely, 21353339000017 is an apocalyptic number.
It is an amenable number.
1353339000017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353339000017 is an equidigital number, since it uses as much as digits as its factorization.
1353339000017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25515, while the sum is 35.
The spelling of 1353339000017 in words is "one trillion, three hundred fifty-three billion, three hundred thirty-nine million, seventeen", and thus it is an aban number.
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