Base | Representation |
---|---|
bin | 10011101100011101010… |
… | …010110010111000010111 |
3 | 11210101101012110201010212 |
4 | 103230131102302320113 |
5 | 134133233434231003 |
6 | 2513425103040035 |
7 | 166531444405031 |
oct | 23543522627027 |
9 | 4711335421125 |
10 | 1353406164503 |
11 | 481a81551028 |
12 | 19a370ba001b |
13 | 9a81973ab03 |
14 | 4971040cc51 |
15 | 2531283ddd8 |
hex | 13b1d4b2e17 |
1353406164503 has 2 divisors, whose sum is σ = 1353406164504. Its totient is φ = 1353406164502.
The previous prime is 1353406164499. The next prime is 1353406164611. The reversal of 1353406164503 is 3054616043531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1353406164503 - 22 = 1353406164499 is a prime.
It is a super-2 number, since 2×13534061645032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1353406164403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676703082251 + 676703082252.
It is an arithmetic number, because the mean of its divisors is an integer number (676703082252).
Almost surely, 21353406164503 is an apocalyptic number.
1353406164503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353406164503 is an equidigital number, since it uses as much as digits as its factorization.
1353406164503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 1353406164503 in words is "one trillion, three hundred fifty-three billion, four hundred six million, one hundred sixty-four thousand, five hundred three".
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