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1353406164503 is a prime number
BaseRepresentation
bin10011101100011101010…
…010110010111000010111
311210101101012110201010212
4103230131102302320113
5134133233434231003
62513425103040035
7166531444405031
oct23543522627027
94711335421125
101353406164503
11481a81551028
1219a370ba001b
139a81973ab03
144971040cc51
152531283ddd8
hex13b1d4b2e17

1353406164503 has 2 divisors, whose sum is σ = 1353406164504. Its totient is φ = 1353406164502.

The previous prime is 1353406164499. The next prime is 1353406164611. The reversal of 1353406164503 is 3054616043531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1353406164503 - 22 = 1353406164499 is a prime.

It is a super-2 number, since 2×13534061645032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1353406164403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676703082251 + 676703082252.

It is an arithmetic number, because the mean of its divisors is an integer number (676703082252).

Almost surely, 21353406164503 is an apocalyptic number.

1353406164503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353406164503 is an equidigital number, since it uses as much as digits as its factorization.

1353406164503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 1353406164503 in words is "one trillion, three hundred fifty-three billion, four hundred six million, one hundred sixty-four thousand, five hundred three".