Base | Representation |
---|---|
bin | 10011101100011101100… |
… | …111100011001011111011 |
3 | 11210101101120201010102202 |
4 | 103230131213203023323 |
5 | 134133241332331433 |
6 | 2513425415420415 |
7 | 166531541555165 |
oct | 23543547431373 |
9 | 4711346633382 |
10 | 1353411605243 |
11 | 481a84627805 |
12 | 19a37298470b |
13 | 9a81a8c4399 |
14 | 49711027935 |
15 | 25313065ee8 |
hex | 13b1d9e32fb |
1353411605243 has 2 divisors, whose sum is σ = 1353411605244. Its totient is φ = 1353411605242.
The previous prime is 1353411605233. The next prime is 1353411605279. The reversal of 1353411605243 is 3425061143531.
It is a weak prime.
It is an emirp because it is prime and its reverse (3425061143531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1353411605243 - 222 = 1353407410939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1353411605197 and 1353411605206.
It is not a weakly prime, because it can be changed into another prime (1353411605233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676705802621 + 676705802622.
It is an arithmetic number, because the mean of its divisors is an integer number (676705802622).
Almost surely, 21353411605243 is an apocalyptic number.
1353411605243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353411605243 is an equidigital number, since it uses as much as digits as its factorization.
1353411605243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 1353411605243 its reverse (3425061143531), we get a palindrome (4778472748774).
The spelling of 1353411605243 in words is "one trillion, three hundred fifty-three billion, four hundred eleven million, six hundred five thousand, two hundred forty-three".
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