Base | Representation |
---|---|
bin | 1100010011110010100110… |
… | …1100110001101011000011 |
3 | 1202220211222121001212000211 |
4 | 3010330221230301223003 |
5 | 3233220410214201342 |
6 | 44441255423454551 |
7 | 2564544434033332 |
oct | 304745154615303 |
9 | 52824877055024 |
10 | 13534141553347 |
11 | 4348885088588 |
12 | 1627010757457 |
13 | 77235822205c |
14 | 34b0ad733d19 |
15 | 1870c27cac17 |
hex | c4f29b31ac3 |
13534141553347 has 2 divisors, whose sum is σ = 13534141553348. Its totient is φ = 13534141553346.
The previous prime is 13534141553341. The next prime is 13534141553381. The reversal of 13534141553347 is 74335514143531.
13534141553347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13534141553347 - 239 = 12984385739459 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13534141553347.
It is not a weakly prime, because it can be changed into another prime (13534141553341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767070776673 + 6767070776674.
It is an arithmetic number, because the mean of its divisors is an integer number (6767070776674).
Almost surely, 213534141553347 is an apocalyptic number.
13534141553347 is a deficient number, since it is larger than the sum of its proper divisors (1).
13534141553347 is an equidigital number, since it uses as much as digits as its factorization.
13534141553347 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4536000, while the sum is 49.
Adding to 13534141553347 its reverse (74335514143531), we get a palindrome (87869655696878).
The spelling of 13534141553347 in words is "thirteen trillion, five hundred thirty-four billion, one hundred forty-one million, five hundred fifty-three thousand, three hundred forty-seven".
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