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13534141553381 is a prime number
BaseRepresentation
bin1100010011110010100110…
…1100110001101011100101
31202220211222121001212002002
43010330221230301223211
53233220410214202011
644441255423455045
72564544434033411
oct304745154615345
952824877055062
1013534141553381
114348885088609
121627010757485
13772358222087
1434b0ad733d41
151870c27cac3b
hexc4f29b31ae5

13534141553381 has 2 divisors, whose sum is σ = 13534141553382. Its totient is φ = 13534141553380.

The previous prime is 13534141553347. The next prime is 13534141553467. The reversal of 13534141553381 is 18335514143531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10488886209025 + 3045255344356 = 3238655^2 + 1745066^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13534141553381 is a prime.

It is a super-2 number, since 2×135341415533812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13534141553341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767070776690 + 6767070776691.

It is an arithmetic number, because the mean of its divisors is an integer number (6767070776691).

Almost surely, 213534141553381 is an apocalyptic number.

It is an amenable number.

13534141553381 is a deficient number, since it is larger than the sum of its proper divisors (1).

13534141553381 is an equidigital number, since it uses as much as digits as its factorization.

13534141553381 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296000, while the sum is 47.

The spelling of 13534141553381 in words is "thirteen trillion, five hundred thirty-four billion, one hundred forty-one million, five hundred fifty-three thousand, three hundred eighty-one".