Base | Representation |
---|---|
bin | 11001001101011001… |
… | …11000110011110111 |
3 | 1021221012222202101111 |
4 | 30212230320303313 |
5 | 210204224000002 |
6 | 10114552535451 |
7 | 656250554104 |
oct | 144654706367 |
9 | 37835882344 |
10 | 13534203127 |
11 | 5815783145 |
12 | 27586b1587 |
13 | 1378c70c23 |
14 | 9256a5aab |
15 | 5432c43d7 |
hex | 326b38cf7 |
13534203127 has 2 divisors, whose sum is σ = 13534203128. Its totient is φ = 13534203126.
The previous prime is 13534203113. The next prime is 13534203157. The reversal of 13534203127 is 72130243531.
It is a weak prime.
It is an emirp because it is prime and its reverse (72130243531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13534203127 - 27 = 13534202999 is a prime.
It is a super-3 number, since 3×135342031273 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13534203157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767101563 + 6767101564.
It is an arithmetic number, because the mean of its divisors is an integer number (6767101564).
Almost surely, 213534203127 is an apocalyptic number.
13534203127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13534203127 is an equidigital number, since it uses as much as digits as its factorization.
13534203127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 13534203127 its reverse (72130243531), we get a palindrome (85664446658).
The spelling of 13534203127 in words is "thirteen billion, five hundred thirty-four million, two hundred three thousand, one hundred twenty-seven".
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