Base | Representation |
---|---|
bin | 10011101100011111010… |
… | …101000011100000100011 |
3 | 11210101110120201112210012 |
4 | 103230133111003200203 |
5 | 134133321204430311 |
6 | 2513432322555135 |
7 | 166532340554333 |
oct | 23543725034043 |
9 | 4711416645705 |
10 | 1353440311331 |
11 | 481a99854049 |
12 | 19a380508aab |
13 | 9a823835434 |
14 | 49714b7b0c3 |
15 | 2531583678b |
hex | 13b1f543823 |
1353440311331 has 2 divisors, whose sum is σ = 1353440311332. Its totient is φ = 1353440311330.
The previous prime is 1353440311297. The next prime is 1353440311357. The reversal of 1353440311331 is 1331130443531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1353440311331 - 222 = 1353436117027 is a prime.
It is a super-2 number, since 2×13534403113312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1353440316331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676720155665 + 676720155666.
It is an arithmetic number, because the mean of its divisors is an integer number (676720155666).
Almost surely, 21353440311331 is an apocalyptic number.
1353440311331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353440311331 is an equidigital number, since it uses as much as digits as its factorization.
1353440311331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 1353440311331 its reverse (1331130443531), we get a palindrome (2684570754862).
The spelling of 1353440311331 in words is "one trillion, three hundred fifty-three billion, four hundred forty million, three hundred eleven thousand, three hundred thirty-one".
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