Base | Representation |
---|---|
bin | 11001001101100010… |
… | …11111111110110111 |
3 | 1021221022021011212011 |
4 | 30212301133332313 |
5 | 210210031142101 |
6 | 10115034505051 |
7 | 656264051002 |
oct | 144661377667 |
9 | 37838234764 |
10 | 13535412151 |
11 | 5816429538 |
12 | 2758b95187 |
13 | 13792a5321 |
14 | 9258dc539 |
15 | 543462751 |
hex | 326c5ffb7 |
13535412151 has 2 divisors, whose sum is σ = 13535412152. Its totient is φ = 13535412150.
The previous prime is 13535412131. The next prime is 13535412157. The reversal of 13535412151 is 15121453531.
It is a strong prime.
It is an emirp because it is prime and its reverse (15121453531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13535412151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13535412157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767706075 + 6767706076.
It is an arithmetic number, because the mean of its divisors is an integer number (6767706076).
Almost surely, 213535412151 is an apocalyptic number.
13535412151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13535412151 is an equidigital number, since it uses as much as digits as its factorization.
13535412151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9000, while the sum is 31.
Adding to 13535412151 its reverse (15121453531), we get a palindrome (28656865682).
The spelling of 13535412151 in words is "thirteen billion, five hundred thirty-five million, four hundred twelve thousand, one hundred fifty-one".
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