Base | Representation |
---|---|
bin | 111111000001111000… |
… | …0001100001001011111 |
3 | 110221101002020200102111 |
4 | 1332003300030021133 |
5 | 4204201213343033 |
6 | 142103031134451 |
7 | 12531131464345 |
oct | 1760360141137 |
9 | 427332220374 |
10 | 135354434143 |
11 | 5244905a815 |
12 | 22295b14427 |
13 | c9c12ac966 |
14 | 67a066d995 |
15 | 37c2e7c7cd |
hex | 1f83c0c25f |
135354434143 has 2 divisors, whose sum is σ = 135354434144. Its totient is φ = 135354434142.
The previous prime is 135354434071. The next prime is 135354434147. The reversal of 135354434143 is 341434453531.
It is a strong prime.
It is an emirp because it is prime and its reverse (341434453531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135354434143 - 225 = 135320879711 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135354434096 and 135354434105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135354434147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67677217071 + 67677217072.
It is an arithmetic number, because the mean of its divisors is an integer number (67677217072).
Almost surely, 2135354434143 is an apocalyptic number.
135354434143 is a deficient number, since it is larger than the sum of its proper divisors (1).
135354434143 is an equidigital number, since it uses as much as digits as its factorization.
135354434143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 518400, while the sum is 40.
Adding to 135354434143 its reverse (341434453531), we get a palindrome (476788887674).
The spelling of 135354434143 in words is "one hundred thirty-five billion, three hundred fifty-four million, four hundred thirty-four thousand, one hundred forty-three".
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