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135354434143 is a prime number
BaseRepresentation
bin111111000001111000…
…0001100001001011111
3110221101002020200102111
41332003300030021133
54204201213343033
6142103031134451
712531131464345
oct1760360141137
9427332220374
10135354434143
115244905a815
1222295b14427
13c9c12ac966
1467a066d995
1537c2e7c7cd
hex1f83c0c25f

135354434143 has 2 divisors, whose sum is σ = 135354434144. Its totient is φ = 135354434142.

The previous prime is 135354434071. The next prime is 135354434147. The reversal of 135354434143 is 341434453531.

It is a strong prime.

It is an emirp because it is prime and its reverse (341434453531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135354434143 - 225 = 135320879711 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135354434096 and 135354434105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135354434147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67677217071 + 67677217072.

It is an arithmetic number, because the mean of its divisors is an integer number (67677217072).

Almost surely, 2135354434143 is an apocalyptic number.

135354434143 is a deficient number, since it is larger than the sum of its proper divisors (1).

135354434143 is an equidigital number, since it uses as much as digits as its factorization.

135354434143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 518400, while the sum is 40.

Adding to 135354434143 its reverse (341434453531), we get a palindrome (476788887674).

The spelling of 135354434143 in words is "one hundred thirty-five billion, three hundred fifty-four million, four hundred thirty-four thousand, one hundred forty-three".