Base | Representation |
---|---|
bin | 11001001101100011… |
… | …11000011101110001 |
3 | 1021221022110021102022 |
4 | 30212301320131301 |
5 | 210210042344213 |
6 | 10115041001225 |
7 | 656264646242 |
oct | 144661703561 |
9 | 37838407368 |
10 | 13535512433 |
11 | 5816497913 |
12 | 2759023215 |
13 | 137930bb71 |
14 | 925926cc9 |
15 | 543482308 |
hex | 326c78771 |
13535512433 has 2 divisors, whose sum is σ = 13535512434. Its totient is φ = 13535512432.
The previous prime is 13535512427. The next prime is 13535512447. The reversal of 13535512433 is 33421553531.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7929546304 + 5605966129 = 89048^2 + 74873^2 .
It is a cyclic number.
It is not a de Polignac number, because 13535512433 - 226 = 13468403569 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13535512393 and 13535512402.
It is not a weakly prime, because it can be changed into another prime (13535512493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767756216 + 6767756217.
It is an arithmetic number, because the mean of its divisors is an integer number (6767756217).
Almost surely, 213535512433 is an apocalyptic number.
It is an amenable number.
13535512433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13535512433 is an equidigital number, since it uses as much as digits as its factorization.
13535512433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 81000, while the sum is 35.
The spelling of 13535512433 in words is "thirteen billion, five hundred thirty-five million, five hundred twelve thousand, four hundred thirty-three".
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