Base | Representation |
---|---|
bin | 11001001101101001… |
… | …00011101100100001 |
3 | 1021221100202220111121 |
4 | 30212310203230201 |
5 | 210210232320133 |
6 | 10115104012241 |
7 | 656303630104 |
oct | 144664435441 |
9 | 37840686447 |
10 | 13536213793 |
11 | 5816926853 |
12 | 2759301081 |
13 | 13794c617b |
14 | 925a6a73b |
15 | 54357002d |
hex | 326d23b21 |
13536213793 has 2 divisors, whose sum is σ = 13536213794. Its totient is φ = 13536213792.
The previous prime is 13536213791. The next prime is 13536213799. The reversal of 13536213793 is 39731263531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7521745984 + 6014467809 = 86728^2 + 77553^2 .
It is a cyclic number.
It is not a de Polignac number, because 13536213793 - 21 = 13536213791 is a prime.
Together with 13536213791, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13536213791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6768106896 + 6768106897.
It is an arithmetic number, because the mean of its divisors is an integer number (6768106897).
Almost surely, 213536213793 is an apocalyptic number.
It is an amenable number.
13536213793 is a deficient number, since it is larger than the sum of its proper divisors (1).
13536213793 is an equidigital number, since it uses as much as digits as its factorization.
13536213793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 306180, while the sum is 43.
The spelling of 13536213793 in words is "thirteen billion, five hundred thirty-six million, two hundred thirteen thousand, seven hundred ninety-three".
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