Base | Representation |
---|---|
bin | 10011101100111000001… |
… | …011111000111110111001 |
3 | 11210102112122102202122022 |
4 | 103230320023320332321 |
5 | 134140144434324241 |
6 | 2513541541204225 |
7 | 166545563336354 |
oct | 23547013707671 |
9 | 4712478382568 |
10 | 1353857339321 |
11 | 48219319a383 |
12 | 19a478100675 |
13 | 9a88c059466 |
14 | 497542d529b |
15 | 2533c26054b |
hex | 13b382f8fb9 |
1353857339321 has 2 divisors, whose sum is σ = 1353857339322. Its totient is φ = 1353857339320.
The previous prime is 1353857339287. The next prime is 1353857339333. The reversal of 1353857339321 is 1239337583531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1347373063696 + 6484275625 = 1160764^2 + 80525^2 .
It is an emirp because it is prime and its reverse (1239337583531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1353857339321 - 26 = 1353857339257 is a prime.
It is not a weakly prime, because it can be changed into another prime (1353857339381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676928669660 + 676928669661.
It is an arithmetic number, because the mean of its divisors is an integer number (676928669661).
Almost surely, 21353857339321 is an apocalyptic number.
It is an amenable number.
1353857339321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353857339321 is an equidigital number, since it uses as much as digits as its factorization.
1353857339321 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6123600, while the sum is 53.
The spelling of 1353857339321 in words is "one trillion, three hundred fifty-three billion, eight hundred fifty-seven million, three hundred thirty-nine thousand, three hundred twenty-one".
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