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135396493 is a prime number
BaseRepresentation
bin10000001000111…
…11110010001101
3100102202212001221
420010133302031
5234130141433
621234003341
73232564651
oct1004376215
9312685057
10135396493
116a478431
1239416551
1322087b8b
1413da6a61
15bd4772d
hex811fc8d

135396493 has 2 divisors, whose sum is σ = 135396494. Its totient is φ = 135396492.

The previous prime is 135396467. The next prime is 135396509. The reversal of 135396493 is 394693531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133125444 + 2271049 = 11538^2 + 1507^2 .

It is a cyclic number.

It is not a de Polignac number, because 135396493 - 213 = 135388301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135396403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67698246 + 67698247.

It is an arithmetic number, because the mean of its divisors is an integer number (67698247).

Almost surely, 2135396493 is an apocalyptic number.

It is an amenable number.

135396493 is a deficient number, since it is larger than the sum of its proper divisors (1).

135396493 is an equidigital number, since it uses as much as digits as its factorization.

135396493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 262440, while the sum is 43.

The square root of 135396493 is about 11635.9998710897. Note that the first 3 decimals coincide. The cubic root of 135396493 is about 513.4945105376.

The spelling of 135396493 in words is "one hundred thirty-five million, three hundred ninety-six thousand, four hundred ninety-three".