1354015010041 has 2 divisors, whose sum is σ = 1354015010042. Its totient is φ = 1354015010040.

The previous prime is 1354015009993. The next prime is 1354015010057. The reversal of 1354015010041 is 1400105104531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1245223882816 + 108791127225 = 1115896^2 + 329835^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354015010041 - 2²³ = 1354006621433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1354015009988 and 1354015010015.

It is not a weakly prime, because it can be changed into another prime (1354015010641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677007505020 + 677007505021.

It is an arithmetic number, because the mean of its divisors is an integer number (677007505021).

Almost surely, 2^{1354015010041} is an apocalyptic number.

It is an amenable number.

1354015010041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354015010041 is an equidigital number, since it uses as much as digits as its factorization.

1354015010041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

The spelling of 1354015010041 in words is "one trillion, three hundred fifty-four billion, fifteen million, ten thousand, forty-one".