Base | Representation |
---|---|
bin | 10011101101000010110… |
… | …010100001001100010101 |
3 | 11210110000001011221021102 |
4 | 103231002302201030111 |
5 | 134141031010101103 |
6 | 2514011334155445 |
7 | 166553153422400 |
oct | 23550262411425 |
9 | 4713001157242 |
10 | 1354035237653 |
11 | 482274656a9a |
12 | 19a5077b2b85 |
13 | 9a8b9b75847 |
14 | 4976dba2d37 |
15 | 2534cba0e88 |
hex | 13b42ca1315 |
1354035237653 has 24 divisors (see below), whose sum is σ = 1598833720800. Its totient is φ = 1143120087648.
The previous prime is 1354035237637. The next prime is 1354035237683. The reversal of 1354035237653 is 3567325304531.
It is not a de Polignac number, because 1354035237653 - 24 = 1354035237637 is a prime.
It is a super-2 number, since 2×13540352376532 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1354035237598 and 1354035237607.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1354035237683) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27615083 + ... + 27664071.
It is an arithmetic number, because the mean of its divisors is an integer number (66618071700).
Almost surely, 21354035237653 is an apocalyptic number.
It is an amenable number.
1354035237653 is a deficient number, since it is larger than the sum of its proper divisors (244798483147).
1354035237653 is an equidigital number, since it uses as much as digits as its factorization.
1354035237653 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57489 (or 57482 counting only the distinct ones).
The product of its (nonzero) digits is 3402000, while the sum is 47.
The spelling of 1354035237653 in words is "one trillion, three hundred fifty-four billion, thirty-five million, two hundred thirty-seven thousand, six hundred fifty-three".
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