Base | Representation |
---|---|
bin | 111111000011011111… |
… | …1100001010110100111 |
3 | 110221111212111222112001 |
4 | 1332012333201112213 |
5 | 4204304122103212 |
6 | 142112252110131 |
7 | 12532361452162 |
oct | 1760677412647 |
9 | 427455458461 |
10 | 135408784807 |
11 | 5247680221a |
12 | 222b0165347 |
13 | c9cc62c40a |
14 | 67a797aad9 |
15 | 37c7b16657 |
hex | 1f86fe15a7 |
135408784807 has 2 divisors, whose sum is σ = 135408784808. Its totient is φ = 135408784806.
The previous prime is 135408784799. The next prime is 135408784811. The reversal of 135408784807 is 708487804531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135408784807 - 23 = 135408784799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135408784837) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67704392403 + 67704392404.
It is an arithmetic number, because the mean of its divisors is an integer number (67704392404).
Almost surely, 2135408784807 is an apocalyptic number.
135408784807 is a deficient number, since it is larger than the sum of its proper divisors (1).
135408784807 is an equidigital number, since it uses as much as digits as its factorization.
135408784807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6021120, while the sum is 55.
The spelling of 135408784807 in words is "one hundred thirty-five billion, four hundred eight million, seven hundred eighty-four thousand, eight hundred seven".
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