Base | Representation |
---|---|
bin | 11001001110010000… |
… | …00100110111110001 |
3 | 1021221201101212012012 |
4 | 30213020010313301 |
5 | 210213040033132 |
6 | 10115405412305 |
7 | 656365260266 |
oct | 144710046761 |
9 | 37851355165 |
10 | 13541330417 |
11 | 5819800a6a |
12 | 275ab6a095 |
13 | 137a598064 |
14 | 9265dd26d |
15 | 543c310b2 |
hex | 327204df1 |
13541330417 has 2 divisors, whose sum is σ = 13541330418. Its totient is φ = 13541330416.
The previous prime is 13541330393. The next prime is 13541330459. The reversal of 13541330417 is 71403314531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12700388416 + 840942001 = 112696^2 + 28999^2 .
It is an emirp because it is prime and its reverse (71403314531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13541330417 - 26 = 13541330353 is a prime.
It is not a weakly prime, because it can be changed into another prime (13541330617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770665208 + 6770665209.
It is an arithmetic number, because the mean of its divisors is an integer number (6770665209).
Almost surely, 213541330417 is an apocalyptic number.
It is an amenable number.
13541330417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13541330417 is an equidigital number, since it uses as much as digits as its factorization.
13541330417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 13541330417 its reverse (71403314531), we get a palindrome (84944644948).
The spelling of 13541330417 in words is "thirteen billion, five hundred forty-one million, three hundred thirty thousand, four hundred seventeen".
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