Base | Representation |
---|---|
bin | 111111000011101000… |
… | …1100011011110100111 |
3 | 110221112012102011011002 |
4 | 1332013101203132213 |
5 | 4204311324341403 |
6 | 142112541303515 |
7 | 12532446601322 |
oct | 1760721433647 |
9 | 427465364132 |
10 | 135413512103 |
11 | 52479440981 |
12 | 222b1864b9b |
13 | ca005c602c |
14 | 67a844b7b9 |
15 | 37c824c188 |
hex | 1f874637a7 |
135413512103 has 2 divisors, whose sum is σ = 135413512104. Its totient is φ = 135413512102.
The previous prime is 135413511971. The next prime is 135413512123. The reversal of 135413512103 is 301215314531.
It is a strong prime.
It is an emirp because it is prime and its reverse (301215314531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135413512103 - 232 = 131118544807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135413512123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67706756051 + 67706756052.
It is an arithmetic number, because the mean of its divisors is an integer number (67706756052).
Almost surely, 2135413512103 is an apocalyptic number.
135413512103 is a deficient number, since it is larger than the sum of its proper divisors (1).
135413512103 is an equidigital number, since it uses as much as digits as its factorization.
135413512103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 135413512103 its reverse (301215314531), we get a palindrome (436628826634).
The spelling of 135413512103 in words is "one hundred thirty-five billion, four hundred thirteen million, five hundred twelve thousand, one hundred three".
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