Base | Representation |
---|---|
bin | 11110110010100111101111… |
… | …000001100100000110111011 |
3 | 122202111000210000021110212121 |
4 | 132302213233001210012323 |
5 | 120222210212203242001 |
6 | 1200003034345422111 |
7 | 40344526453665352 |
oct | 3662475701440673 |
9 | 582430700243777 |
10 | 135420034040251 |
11 | 3a17034a906044 |
12 | 1323138749a937 |
13 | 5a7409272036c |
14 | 2562516730999 |
15 | 109c8bc4056a1 |
hex | 7b29ef0641bb |
135420034040251 has 2 divisors, whose sum is σ = 135420034040252. Its totient is φ = 135420034040250.
The previous prime is 135420034040233. The next prime is 135420034040323. The reversal of 135420034040251 is 152040430024531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135420034040251 - 223 = 135420025651643 is a prime.
It is not a weakly prime, because it can be changed into another prime (135420034047251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67710017020125 + 67710017020126.
It is an arithmetic number, because the mean of its divisors is an integer number (67710017020126).
Almost surely, 2135420034040251 is an apocalyptic number.
135420034040251 is a deficient number, since it is larger than the sum of its proper divisors (1).
135420034040251 is an equidigital number, since it uses as much as digits as its factorization.
135420034040251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 135420034040251 its reverse (152040430024531), we get a palindrome (287460464064782).
The spelling of 135420034040251 in words is "one hundred thirty-five trillion, four hundred twenty billion, thirty-four million, forty thousand, two hundred fifty-one".
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