Base | Representation |
---|---|
bin | 11110110010101000101110… |
… | …101001000000010011111111 |
3 | 122202111010112101121010101001 |
4 | 132302220232221000103333 |
5 | 120222214403421001444 |
6 | 1200003332313431131 |
7 | 40344565063633162 |
oct | 3662505651002377 |
9 | 582433471533331 |
10 | 135421101343999 |
11 | 3a170848319159 |
12 | 13231624a0b4a7 |
13 | 5a74202893a43 |
14 | 25625b839bad9 |
15 | 109c930e7d8d4 |
hex | 7b2a2ea404ff |
135421101343999 has 2 divisors, whose sum is σ = 135421101344000. Its totient is φ = 135421101343998.
The previous prime is 135421101343993. The next prime is 135421101344003. The reversal of 135421101343999 is 999343101124531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135421101343999 - 25 = 135421101343967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135421101343993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67710550671999 + 67710550672000.
It is an arithmetic number, because the mean of its divisors is an integer number (67710550672000).
Almost surely, 2135421101343999 is an apocalyptic number.
135421101343999 is a deficient number, since it is larger than the sum of its proper divisors (1).
135421101343999 is an equidigital number, since it uses as much as digits as its factorization.
135421101343999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3149280, while the sum is 55.
The spelling of 135421101343999 in words is "one hundred thirty-five trillion, four hundred twenty-one billion, one hundred one million, three hundred forty-three thousand, nine hundred ninety-nine".
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