Base | Representation |
---|---|
bin | 11001001110010110… |
… | …11010011010001011 |
3 | 1021221210001021222122 |
4 | 30213023122122023 |
5 | 210213301030232 |
6 | 10115440241455 |
7 | 656405562266 |
oct | 144713323213 |
9 | 37853037878 |
10 | 13542205067 |
11 | 581a249116 |
12 | 275b31028b |
13 | 137a8131c1 |
14 | 926789cdd |
15 | 543d55312 |
hex | 3272da68b |
13542205067 has 2 divisors, whose sum is σ = 13542205068. Its totient is φ = 13542205066.
The previous prime is 13542205009. The next prime is 13542205069. The reversal of 13542205067 is 76050224531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13542205067 - 214 = 13542188683 is a prime.
Together with 13542205069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13542205069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771102533 + 6771102534.
It is an arithmetic number, because the mean of its divisors is an integer number (6771102534).
Almost surely, 213542205067 is an apocalyptic number.
13542205067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13542205067 is an equidigital number, since it uses as much as digits as its factorization.
13542205067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
Adding to 13542205067 its reverse (76050224531), we get a palindrome (89592429598).
The spelling of 13542205067 in words is "thirteen billion, five hundred forty-two million, two hundred five thousand, sixty-seven".
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