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1354240117 is a prime number
BaseRepresentation
bin101000010111000…
…0001000001110101
310111101020112012101
41100232001001311
510233141140432
6342214022101
745362564626
oct12056010165
93441215171
101354240117
1163548470a
12319647931
13187749319
14cbbdda4d
157dd564e7
hex50b81075

1354240117 has 2 divisors, whose sum is σ = 1354240118. Its totient is φ = 1354240116.

The previous prime is 1354240103. The next prime is 1354240133. The reversal of 1354240117 is 7110424531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1318706596 + 35533521 = 36314^2 + 5961^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1354240117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354240817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677120058 + 677120059.

It is an arithmetic number, because the mean of its divisors is an integer number (677120059).

Almost surely, 21354240117 is an apocalyptic number.

It is an amenable number.

1354240117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354240117 is an equidigital number, since it uses as much as digits as its factorization.

1354240117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 28.

The square root of 1354240117 is about 36800.0015896739. The cubic root of 1354240117 is about 1106.3653310042.

Adding to 1354240117 its reverse (7110424531), we get a palindrome (8464664648).

The spelling of 1354240117 in words is "one billion, three hundred fifty-four million, two hundred forty thousand, one hundred seventeen".