Base | Representation |
---|---|
bin | 111111000011111100… |
… | …1101000111001001001 |
3 | 110221112221012000022222 |
4 | 1332013321220321021 |
5 | 4204322022120131 |
6 | 142113554423425 |
7 | 12532635114602 |
oct | 1760771507111 |
9 | 427487160288 |
10 | 135424020041 |
11 | 52484368722 |
12 | 222b5291b75 |
13 | ca02834b4b |
14 | 67a99c4da9 |
15 | 37c912587b |
hex | 1f87e68e49 |
135424020041 has 2 divisors, whose sum is σ = 135424020042. Its totient is φ = 135424020040.
The previous prime is 135424019993. The next prime is 135424020071. The reversal of 135424020041 is 140020424531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102797184400 + 32626835641 = 320620^2 + 180629^2 .
It is a cyclic number.
It is not a de Polignac number, because 135424020041 - 26 = 135424019977 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (135424020071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67712010020 + 67712010021.
It is an arithmetic number, because the mean of its divisors is an integer number (67712010021).
Almost surely, 2135424020041 is an apocalyptic number.
It is an amenable number.
135424020041 is a deficient number, since it is larger than the sum of its proper divisors (1).
135424020041 is an equidigital number, since it uses as much as digits as its factorization.
135424020041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 135424020041 its reverse (140020424531), we get a palindrome (275444444572).
The spelling of 135424020041 in words is "one hundred thirty-five billion, four hundred twenty-four million, twenty thousand, forty-one".
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