Base | Representation |
---|---|
bin | 111111000011111100… |
… | …1101000111001100111 |
3 | 110221112221012000101002 |
4 | 1332013321220321213 |
5 | 4204322022120241 |
6 | 142113554423515 |
7 | 12532635114644 |
oct | 1760771507147 |
9 | 427487160332 |
10 | 135424020071 |
11 | 5248436874a |
12 | 222b5291b9b |
13 | ca02834b72 |
14 | 67a99c4dcb |
15 | 37c912589b |
hex | 1f87e68e67 |
135424020071 has 2 divisors, whose sum is σ = 135424020072. Its totient is φ = 135424020070.
The previous prime is 135424020041. The next prime is 135424020073. The reversal of 135424020071 is 170020424531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135424020071 - 210 = 135424019047 is a prime.
It is a super-2 number, since 2×1354240200712 (a number of 23 digits) contains 22 as substring.
Together with 135424020073, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135424020073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67712010035 + 67712010036.
It is an arithmetic number, because the mean of its divisors is an integer number (67712010036).
Almost surely, 2135424020071 is an apocalyptic number.
135424020071 is a deficient number, since it is larger than the sum of its proper divisors (1).
135424020071 is an equidigital number, since it uses as much as digits as its factorization.
135424020071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 29.
The spelling of 135424020071 in words is "one hundred thirty-five billion, four hundred twenty-four million, twenty thousand, seventy-one".
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