Base | Representation |
---|---|
bin | 10011101101001111110… |
… | …011110000001010011011 |
3 | 11210110120021012012011022 |
4 | 103231033303300022123 |
5 | 134142002414234143 |
6 | 2514045135553055 |
7 | 166561445135525 |
oct | 23551763601233 |
9 | 4713507165138 |
10 | 1354253664923 |
11 | 4823769856a5 |
12 | 19a56898b78b |
13 | 9a9231b2453 |
14 | 49790bc0a15 |
15 | 25361e4a268 |
hex | 13b4fcf029b |
1354253664923 has 2 divisors, whose sum is σ = 1354253664924. Its totient is φ = 1354253664922.
The previous prime is 1354253664899. The next prime is 1354253664949. The reversal of 1354253664923 is 3294663524531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1354253664923 - 210 = 1354253663899 is a prime.
It is not a weakly prime, because it can be changed into another prime (1354253664983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677126832461 + 677126832462.
It is an arithmetic number, because the mean of its divisors is an integer number (677126832462).
Almost surely, 21354253664923 is an apocalyptic number.
1354253664923 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354253664923 is an equidigital number, since it uses as much as digits as its factorization.
1354253664923 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13996800, while the sum is 53.
The spelling of 1354253664923 in words is "one trillion, three hundred fifty-four billion, two hundred fifty-three million, six hundred sixty-four thousand, nine hundred twenty-three".
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