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1354311044238 = 23497345388801
BaseRepresentation
bin10011101101010011001…
…110101000110010001110
311210110201021011100210010
4103231103032220302032
5134142112111403423
62514054545454050
7166563042636255
oct23552316506216
94713637140703
101354311044238
114823a6306619
1219a584041326
139a9320525c9
144979867979c
1525366ed1693
hex13b533a8c8e

1354311044238 has 16 divisors (see below), whose sum is σ = 2709166813776. Its totient is φ = 451346227200.

The previous prime is 1354311044237. The next prime is 1354311044267. The reversal of 1354311044238 is 8324401134531.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1354311044196 and 1354311044205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1354311044237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22664563 + ... + 22724238.

It is an arithmetic number, because the mean of its divisors is an integer number (169322925861).

Almost surely, 21354311044238 is an apocalyptic number.

1354311044238 is an abundant number, since it is smaller than the sum of its proper divisors (1354855769538).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1354311044238 is a wasteful number, since it uses less digits than its factorization.

1354311044238 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45393779.

The product of its (nonzero) digits is 138240, while the sum is 39.

Adding to 1354311044238 its reverse (8324401134531), we get a palindrome (9678712178769).

The spelling of 1354311044238 in words is "one trillion, three hundred fifty-four billion, three hundred eleven million, forty-four thousand, two hundred thirty-eight".

Divisors: 1 2 3 6 4973 9946 14919 29838 45388801 90777602 136166403 272332806 225718507373 451437014746 677155522119 1354311044238