Base | Representation |
---|---|
bin | 11001001110011101… |
… | …10111100101110111 |
3 | 1021221211202022201212 |
4 | 30213032313211313 |
5 | 210214014023111 |
6 | 10115511512035 |
7 | 656416354502 |
oct | 144716674567 |
9 | 37854668655 |
10 | 13543111031 |
11 | 581a80784a |
12 | 275b68861b |
13 | 137aa6c688 |
14 | 926944139 |
15 | 543e8398b |
hex | 3273b7977 |
13543111031 has 2 divisors, whose sum is σ = 13543111032. Its totient is φ = 13543111030.
The previous prime is 13543111003. The next prime is 13543111039. The reversal of 13543111031 is 13011134531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13543111031 - 226 = 13476002167 is a prime.
It is a super-2 number, since 2×135431110312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13543110988 and 13543111006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13543111039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771555515 + 6771555516.
It is an arithmetic number, because the mean of its divisors is an integer number (6771555516).
Almost surely, 213543111031 is an apocalyptic number.
13543111031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13543111031 is an equidigital number, since it uses as much as digits as its factorization.
13543111031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 13543111031 its reverse (13011134531), we get a palindrome (26554245562).
The spelling of 13543111031 in words is "thirteen billion, five hundred forty-three million, one hundred eleven thousand, thirty-one".
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