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1354324144073 is a prime number
BaseRepresentation
bin10011101101010100000…
…000100110111111001001
311210110202011210220101012
4103231110000212333021
5134142123440102243
62514100134333305
7166563262166225
oct23552400467711
94713664726335
101354324144073
1148240274372a
1219a5884ba235
139a93498b0a4
144979a2c9785
152536821cd18
hex13b54026fc9

1354324144073 has 2 divisors, whose sum is σ = 1354324144074. Its totient is φ = 1354324144072.

The previous prime is 1354324144013. The next prime is 1354324144081. The reversal of 1354324144073 is 3704414234531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 816342969289 + 537981174784 = 903517^2 + 733472^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354324144073 - 224 = 1354307366857 is a prime.

It is a super-2 number, since 2×13543241440732 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1354324144073.

It is not a weakly prime, because it can be changed into another prime (1354324144013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677162072036 + 677162072037.

It is an arithmetic number, because the mean of its divisors is an integer number (677162072037).

Almost surely, 21354324144073 is an apocalyptic number.

It is an amenable number.

1354324144073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354324144073 is an equidigital number, since it uses as much as digits as its factorization.

1354324144073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 41.

The spelling of 1354324144073 in words is "one trillion, three hundred fifty-four billion, three hundred twenty-four million, one hundred forty-four thousand, seventy-three".