Base | Representation |
---|---|
bin | 10011101101010100000… |
… | …000100110111110001101 |
3 | 11210110202011210220021222 |
4 | 103231110000212332031 |
5 | 134142123440102023 |
6 | 2514100134333125 |
7 | 166563262166111 |
oct | 23552400467615 |
9 | 4713664726258 |
10 | 1354324144013 |
11 | 482402743685 |
12 | 19a5884ba1a5 |
13 | 9a93498b059 |
14 | 4979a2c9741 |
15 | 2536821ccc8 |
hex | 13b54026f8d |
1354324144013 has 2 divisors, whose sum is σ = 1354324144014. Its totient is φ = 1354324144012.
The previous prime is 1354324143961. The next prime is 1354324144073. The reversal of 1354324144013 is 3104414234531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1226075642089 + 128248501924 = 1107283^2 + 358118^2 .
It is a cyclic number.
It is not a de Polignac number, because 1354324144013 - 210 = 1354324142989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1354324144073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677162072006 + 677162072007.
It is an arithmetic number, because the mean of its divisors is an integer number (677162072007).
Almost surely, 21354324144013 is an apocalyptic number.
It is an amenable number.
1354324144013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354324144013 is an equidigital number, since it uses as much as digits as its factorization.
1354324144013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 1354324144013 its reverse (3104414234531), we get a palindrome (4458738378544).
The spelling of 1354324144013 in words is "one trillion, three hundred fifty-four billion, three hundred twenty-four million, one hundred forty-four thousand, thirteen".
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