Base | Representation |
---|---|
bin | 11110110010110100101111… |
… | …110010100111100100111111 |
3 | 122202112100211201010100212221 |
4 | 132302310233302213210333 |
5 | 120222422320404340411 |
6 | 1200013305003310211 |
7 | 40345532624545243 |
oct | 3662645762474477 |
9 | 582470751110787 |
10 | 135434005543231 |
11 | 3a17626a41001a |
12 | 1323402651b367 |
13 | 5a754ab1623a5 |
14 | 256308010a423 |
15 | 109ce38caa071 |
hex | 7b2d2fca793f |
135434005543231 has 2 divisors, whose sum is σ = 135434005543232. Its totient is φ = 135434005543230.
The previous prime is 135434005543171. The next prime is 135434005543261. The reversal of 135434005543231 is 132345500434531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135434005543231 - 27 = 135434005543103 is a prime.
It is a super-2 number, since 2×1354340055432312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135434005543261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67717002771615 + 67717002771616.
It is an arithmetic number, because the mean of its divisors is an integer number (67717002771616).
Almost surely, 2135434005543231 is an apocalyptic number.
135434005543231 is a deficient number, since it is larger than the sum of its proper divisors (1).
135434005543231 is an equidigital number, since it uses as much as digits as its factorization.
135434005543231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296000, while the sum is 43.
Adding to 135434005543231 its reverse (132345500434531), we get a palindrome (267779505977762).
The spelling of 135434005543231 in words is "one hundred thirty-five trillion, four hundred thirty-four billion, five million, five hundred forty-three thousand, two hundred thirty-one".
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