Base | Representation |
---|---|
bin | 10011101101010101101… |
… | …111010101101110001111 |
3 | 11210110211012102122022021 |
4 | 103231111233111232033 |
5 | 134142203402440333 |
6 | 2514103052431011 |
7 | 166564064003644 |
oct | 23552557255617 |
9 | 4713735378267 |
10 | 1354353171343 |
11 | 48241806a307 |
12 | 19a596178467 |
13 | 9a93a9b23a3 |
14 | 497a00c3dcb |
15 | 2536aa5382d |
hex | 13b55bd5b8f |
1354353171343 has 2 divisors, whose sum is σ = 1354353171344. Its totient is φ = 1354353171342.
The previous prime is 1354353171331. The next prime is 1354353171407. The reversal of 1354353171343 is 3431713534531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1354353171343 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1354353171343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1354353171043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677176585671 + 677176585672.
It is an arithmetic number, because the mean of its divisors is an integer number (677176585672).
Almost surely, 21354353171343 is an apocalyptic number.
1354353171343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354353171343 is an equidigital number, since it uses as much as digits as its factorization.
1354353171343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 680400, while the sum is 43.
The spelling of 1354353171343 in words is "one trillion, three hundred fifty-four billion, three hundred fifty-three million, one hundred seventy-one thousand, three hundred forty-three".
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