Base | Representation |
---|---|
bin | 11001001110100110… |
… | …00010100100010001 |
3 | 1021221220210212202222 |
4 | 30213103002210101 |
5 | 210214304021221 |
6 | 10115551150425 |
7 | 656431560566 |
oct | 144723024421 |
9 | 37856725688 |
10 | 13544204561 |
11 | 5820394398 |
12 | 275bb15415 |
13 | 137b063334 |
14 | 926b4a86d |
15 | 5440ec9ab |
hex | 3274c2911 |
13544204561 has 2 divisors, whose sum is σ = 13544204562. Its totient is φ = 13544204560.
The previous prime is 13544204519. The next prime is 13544204563. The reversal of 13544204561 is 16540244531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11351623936 + 2192580625 = 106544^2 + 46825^2 .
It is an emirp because it is prime and its reverse (16540244531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13544204561 - 218 = 13543942417 is a prime.
Together with 13544204563, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13544204563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6772102280 + 6772102281.
It is an arithmetic number, because the mean of its divisors is an integer number (6772102281).
Almost surely, 213544204561 is an apocalyptic number.
It is an amenable number.
13544204561 is a deficient number, since it is larger than the sum of its proper divisors (1).
13544204561 is an equidigital number, since it uses as much as digits as its factorization.
13544204561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
The spelling of 13544204561 in words is "thirteen billion, five hundred forty-four million, two hundred four thousand, five hundred sixty-one".
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