Base | Representation |
---|---|
bin | 1100010100011000100111… |
… | …0100110010001100001111 |
3 | 1202221211022122011000000222 |
4 | 3011012021310302030033 |
5 | 3233402304103344301 |
6 | 44450104045541555 |
7 | 2565355322064605 |
oct | 305061164621417 |
9 | 52854278130028 |
10 | 13544344199951 |
11 | 4352140222a24 |
12 | 1628b995748bb |
13 | 7732c2bb2356 |
14 | 34b79a767875 |
15 | 1874bd36731b |
hex | c5189d3230f |
13544344199951 has 2 divisors, whose sum is σ = 13544344199952. Its totient is φ = 13544344199950.
The previous prime is 13544344199941. The next prime is 13544344200011. The reversal of 13544344199951 is 15999144344531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13544344199951 - 214 = 13544344183567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13544344199941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6772172099975 + 6772172099976.
It is an arithmetic number, because the mean of its divisors is an integer number (6772172099976).
Almost surely, 213544344199951 is an apocalyptic number.
13544344199951 is a deficient number, since it is larger than the sum of its proper divisors (1).
13544344199951 is an equidigital number, since it uses as much as digits as its factorization.
13544344199951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41990400, while the sum is 62.
The spelling of 13544344199951 in words is "thirteen trillion, five hundred forty-four billion, three hundred forty-four million, one hundred ninety-nine thousand, nine hundred fifty-one".
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