Base | Representation |
---|---|
bin | 111111000100100010… |
… | …0000100000101000001 |
3 | 110221121021220020000212 |
4 | 1332021010010011001 |
5 | 4204342020430144 |
6 | 142115532523505 |
7 | 12533263003232 |
oct | 1761104040501 |
9 | 427537806025 |
10 | 135443530049 |
11 | 524943838a3 |
12 | 222bb920595 |
13 | ca068a6229 |
14 | 67ac423089 |
15 | 37cabcb49e |
hex | 1f89104141 |
135443530049 has 2 divisors, whose sum is σ = 135443530050. Its totient is φ = 135443530048.
The previous prime is 135443530031. The next prime is 135443530067. The reversal of 135443530049 is 940035344531.
It is a balanced prime because it is at equal distance from previous prime (135443530031) and next prime (135443530067).
It can be written as a sum of positive squares in only one way, i.e., 85895886400 + 49547643649 = 293080^2 + 222593^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135443530049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135443529988 and 135443530015.
It is not a weakly prime, because it can be changed into another prime (135443530069) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67721765024 + 67721765025.
It is an arithmetic number, because the mean of its divisors is an integer number (67721765025).
Almost surely, 2135443530049 is an apocalyptic number.
It is an amenable number.
135443530049 is a deficient number, since it is larger than the sum of its proper divisors (1).
135443530049 is an equidigital number, since it uses as much as digits as its factorization.
135443530049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 135443530049 in words is "one hundred thirty-five billion, four hundred forty-three million, five hundred thirty thousand, forty-nine".
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