Base | Representation |
---|---|
bin | 11110110011000110110110… |
… | …110001011100110110100001 |
3 | 122202121020000211100122220222 |
4 | 132303012312301130312201 |
5 | 120223232131201433442 |
6 | 1200030242250212425 |
7 | 40350121523140424 |
oct | 3663066661346641 |
9 | 582536024318828 |
10 | 135453450030497 |
11 | 3a183538307105 |
12 | 13237952424115 |
13 | 5a77289719561 |
14 | 2563da67099bb |
15 | 109d6c5d948d2 |
hex | 7b31b6c5cda1 |
135453450030497 has 2 divisors, whose sum is σ = 135453450030498. Its totient is φ = 135453450030496.
The previous prime is 135453450030433. The next prime is 135453450030571. The reversal of 135453450030497 is 794030054354531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 135340090547776 + 113359482721 = 11633576^2 + 336689^2 .
It is a cyclic number.
It is not a de Polignac number, because 135453450030497 - 26 = 135453450030433 is a prime.
It is not a weakly prime, because it can be changed into another prime (135453450030407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67726725015248 + 67726725015249.
It is an arithmetic number, because the mean of its divisors is an integer number (67726725015249).
Almost surely, 2135453450030497 is an apocalyptic number.
It is an amenable number.
135453450030497 is a deficient number, since it is larger than the sum of its proper divisors (1).
135453450030497 is an equidigital number, since it uses as much as digits as its factorization.
135453450030497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608000, while the sum is 53.
The spelling of 135453450030497 in words is "one hundred thirty-five trillion, four hundred fifty-three billion, four hundred fifty million, thirty thousand, four hundred ninety-seven".
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