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135455521410023 is a prime number
BaseRepresentation
bin11110110011001000110010…
…001111001000101111100111
3122202121102101012000122110012
4132303020302033020233213
5120223300401440110043
61200031224003120435
740350224044442663
oct3663106217105747
9582542335018405
10135455521410023
113a184400577211
121323823007311b
135a775298c6309
1425641218658a3
15109d797b56a18
hex7b32323c8be7

135455521410023 has 2 divisors, whose sum is σ = 135455521410024. Its totient is φ = 135455521410022.

The previous prime is 135455521409987. The next prime is 135455521410109. The reversal of 135455521410023 is 320014125554531.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135455521410023 is a prime.

It is a super-2 number, since 2×1354555214100232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135455521410523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67727760705011 + 67727760705012.

It is an arithmetic number, because the mean of its divisors is an integer number (67727760705012).

Almost surely, 2135455521410023 is an apocalyptic number.

135455521410023 is a deficient number, since it is larger than the sum of its proper divisors (1).

135455521410023 is an equidigital number, since it uses as much as digits as its factorization.

135455521410023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 135455521410023 its reverse (320014125554531), we get a palindrome (455469646964554).

The spelling of 135455521410023 in words is "one hundred thirty-five trillion, four hundred fifty-five billion, five hundred twenty-one million, four hundred ten thousand, twenty-three".